(2x+1)^1/3=5

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Solution for (2x+1)^1/3=5 equation: 


x in (-oo:+oo)

((2*x+1)^1)/3 = 5 // - 5

((2*x+1)^1)/3-5 = 0

(2*x+1)/3-5 = 0

(2*x+1)/3+(-5*3)/3 = 0

2*x-5*3+1 = 0

2*x-14 = 0

(2*x-14)/3 = 0

(2*x-14)/3 = 0 // * 3

2*x-14 = 0

2*x-14 = 0 // + 14

2*x = 14 // : 2

x = 14/2

x = 7

x = 7

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